voltage regulator wiring

My voltage regulator doesn't have an "L" terminal on it. I am trying to figure out how to get power to the ignition switch and the light switch. Should I run the green wire to the "bat" terminal on the regulator? I am about totally lost. I have a 6 volt system with a voltage regulator (3 prong), converted coil ignition, and a 4 position switch. What do I do?

Jamie

Jamie,

Unfortunately, it sounds like you need to go shopping.

Jamie,

When you say your regulator has 3 terminals, do you mean 2 on one side and one on the other side. If so you may have a cut-out instead of a regulator.

On the cut-out the side with one terminal is the "BAT" terminal and on the other side with the two terminals there are a "F" & "GEN" terminals. There is no "L" terminal on a cut-out.

Here is a diagram for a cut-out with a mag.



Here is a link to a diagram with a cut-out and a battery ignition.

http://albums.photo.epson.com/j/ViewPho ... p=61732517

Hope this helps.

ito: to what Jim said. Your power would come form the ampmeter via the lead to the light switch.

Thanks for the info, that looks like what I was thinking for lights. Now where do I take power to run to the coil via the ignition switch. I have a franken-cub. check out the post below to see what I mean.

http://www.farmallcub.com/phpBB2/viewtopic.php?t=28957

Jamie

Power your switch from the same post on the ammeter. You should already have a 2 post switch based on the fact that your are essentially running a battery ignition system with a mag distributor so just run from the ammeter post to one side of the switch, then from the other side of the switch to the coil and then from the other coil primary post to the terminal on the side of the distributor body. I don't know whether you are running a positive or negative ground system but the polarity of the coil is marked on the primary terminals so if you have a positive ground system the positive coil terminal goes to the distributor terminal and vice versa.